Solution: Word Break
Explore how to apply dynamic programming to the Word Break problem, learning to use a lookup table to optimize checking if a string can be segmented into valid dictionary words. Understand time and space complexity considerations and the step-by-step approach to implementing this solution in C++.
Statement
Given a string, s, and a dictionary of strings, wordDict, check if s can be segmented into a space-separated sequence of one or more dictionary words. If yes, return TRUE; else, return FALSE.
Note: The same word in the dictionary may be used multiple times.
Constraints:
-
s.length -
wordDict.length...