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Word Break II

Understand how to break a string into all valid sequences of dictionary words using dynamic programming in C++. Explore solutions that handle multiple word reuse and generate all possible sentences. Practice applying this technique to improve your problem-solving skills for coding interviews.

Statement

You are given a string, s, and an array of strings, wordDict, representing a dictionary. Your task is to add spaces to s to break it up into a sequence of valid words from wordDict. We are required to return an array of all possible sequences of words (sentences). The order in which the sentences are listed is not significant.

Note: The same dictionary word may be reused multiple times in the segmentation.

Constraints:

  • 11 \leq s.length 20\leq 20

  • 11 \leq wordDict.length 1000\leq 1000

  • 11 \leq wordDict[i].length 10\leq 10

  • s and wordDict[i] consist of only lowercase English letters.

  • All the strings of wordDict are unique.

Examples

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Understand the problem

Let’s take a moment to make sure you’ve correctly understood the problem. The quiz below helps you check if you’re solving the correct problem:

Word Break II

1.

What is the output if the following input string and dictionary are provided as input?

s = “pineapplepenapple”

word_dict = [“apple”, “pen”, “applepen”, “pine”, “pineapple”]

A.

[“pine apple pen apple”, “pineapple pen apple”, “pine applepen apple”]

B.

[“pine apple pen apple”, “pine applepen apple”]

C.

[“pineapple pen apple”]

D.

[]


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Figure it out!

We have a game for you to play. Rearrange the logical building blocks to develop a clearer understanding of how to solve this problem.

Sequence - Vertical
Drag and drop the cards to rearrange them in the correct sequence.

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Try it yourself

Implement your solution in the following coding playground:

C++
usercode > main.cpp
vector<string> WordBreak(string s, vector<string> wordDict)
{
// Replace this placeholder return statement with your code
return {};
}
Word Break II