Solution: Insert into a Sorted Circular Linked List
Explore inserting a new value into a sorted circular linked list while keeping it sorted and circular. Learn to handle edge cases where the list is empty, values wrap around, or all nodes share the same value. Understand in-place pointer manipulation and how to find the correct insertion point with linear time complexity and constant space.
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Statement
You’re given a reference to a node, head, in a circular linked list, where the values are sorted in non-decreasing order. The list is circular, so the last node points to the first node. However, the head can be any node in the list—it is not guaranteed to be the node with the smallest value.
Your task is to insert a new value, insertVal, into the list so that it remains sorted and circular after the insertion.
You can choose any of the multiple valid spots where the value can be inserted while maintaining the sort order.
If the list is empty (i.e., the given node is NULL), create a new circular list with a single node containing
insertVal, and return that node.Otherwise, return the
headnode after insertion.
Constraints:
The number of nodes in the list is in the range
. Node.val,insertVal...