Find Median from Data Stream
Understand how to implement a data structure that supports dynamic integer insertion and returns the median in constant time. Learn to use heaps for efficient median finding in streaming data and practice coding this approach ready for technical interviews.
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Statement
Design a data structure that stores a dynamically changing list of integers and can find the median in constant time, MedianOfStream with the following functionality:
Constructor(): Initializes an instance of the class.
insertNum(int num): Adds a new integer
numto the data structure.findMedian(): Returns the median of all integers added so far.
Note: The median is the middle value in a sorted list of integers.
For an odd-sized list (e.g.,
), the median is the middle element: . For an even-sized list (e.g.,
), the median is the average of the two middle elements: .
Constraints:
num, where numis an integer received from the data stream.There will be at least one element in the data structure before the median is computed.
At most,
calls will be made to the function that calculates the median.
Examples
Understand the problem
Take a moment to make sure you’ve correctly understood the problem. The quiz below will help you check if you’re solving the correct problem:
Find Median from a Data Stream
What is the median of the stream after inserting all elements?
25.0
29.0
36.0
14.0
Figure it out!
We have a game for you to play. Rearrange the logical building blocks to develop a clearer understanding of how to solve this problem.
Try it yourself
Implement your solution in the following coding playground.
from heapq import *class MedianOfStream:def __init__(self):# Write your code herepass# This function should take a number and store itdef insert_num(self, num):# Write your code herepass# This function should return the median of the stored numbersdef find_median(self):# Replace this placeholder return statement with your codereturn 0.0