Redundant Connection
Explore how to use the Union Find algorithm to detect and remove redundant connections in an undirected graph. This lesson helps you understand how to transform a graph with cycles into a tree by efficiently finding edges that can be removed, reinforcing connectivity and cycle detection concepts.
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Statement
We’re given an undirected graph consisting of nodes. The graph is represented as list called edges, of length , where edges[i] = [a, b] indicates that there is an edge between nodes a and b in the graph.
Return an edge that can be removed to make the graph a edges.
Constraints:
edges.lengthedges[i].length2-
ab - There are no repeated edges.
- The given graph is connected.
- The graph contains only one cycle.
Example
Understand the problem
Let’s take a moment to make sure we have correctly understood the problem. The quiz below helps us to check that we are solving precisely the right problem:
Redundant Connection
What is the output if the following list of edges is provided as input?
edges = [[1, 2], [2, 3], [3, 4], [1, 4], [1, 5]]
[2, 3]
[3, 4]
[1, 4]
[1, 5]
Figure it out!
We have a game for you to play. Rearrange the logical building blocks to develop a clearer understanding of how to solve this problem.
Try it yourself
Implement your solution in main.py in the following coding playground. You will need the provided supporting code to implement your solution.
Note: To solve this problem, you may need to change the implementation of the functions in the given Union Find class.
"""⬅️ We have provided a union_find.py file under the "Files" tabof this widget. You can use this file to build your solution."""from union_find import UnionFinddef redundant_connection(edges):# Replace this placeholder return statement with your codereturn []