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Solution: Minimum Remove to Make Valid Parentheses

Explore how to apply stack operations to remove invalid parentheses from a string, ensuring the resulting sequence is valid. Learn to traverse the string efficiently, use a last-in-first-out approach, and handle indexing for removal. This lesson helps you implement an optimal solution with O(n) time and space complexity.

Statement

Given a string, s, that may have matchedEach opening parenthesis, (, has a closing parenthesis, ), for it. and unmatchedThere is no corresponding closing parenthesis, ), for an opening parenthesis, (. parentheses, remove the minimum number of parentheses so that the resulting string represents a valid parenthesization. For example, the string “a(b)” represents a valid parenthesization while the string “a(b” doesn’t, since the opening parenthesis doesn’t have any corresponding closing parenthesis.

Constraints:

  • 11 \leq s.length
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