Reverse Nodes in k-Group
Explore how to reverse nodes in k-sized groups within a linked list by efficiently reordering nodes in-place. Understand constraints and methods that avoid extra memory usage, while preserving remaining nodes order and node values.
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Statement
The task is to reverse the nodes in groups of in a given linked list, where is a positive integer, and at most the length of the linked list. If any remaining nodes are not part of a group of , they should remain in their original order.
It is not allowed to change the values of the nodes in the linked list. Only the order of the nodes can be modified.
Note: Use only extra memory space.
Constraints:
Let n be the number of nodes in a linked list.
-
kn -
Node.value
Examples
Understand the problem
Let’s take a moment to make sure you’ve correctly understood the problem. The quiz below helps you check if you’re solving the correct problem:
Reverse Nodes in k-Group
What is the output if the following head of the linked list and value of are given as input?
head → 8 → 0 → 6 → 1 → 0 → 7 → 8 → 7 → 5 → 3 → 5 → 2 → 4 → 9 → NULL
k = 3
head → 1 → 0 → 7 → 8 → 0 → 6 → 3 → 5 → 2 → 8 → 7 → 5 → 4 → 9 → NULL
head → 7 → 0 → 1 → 6 → 0 → 8 → 2 → 5 → 3 → 5 → 7 → 8 → 4 → 9 → NULL
head → 6 → 0 → 8 → 7 → 0 → 1 → 5 → 7 → 8 → 2 → 5 → 3 → 4 → 9 → NULL
head → 8 → 0 → 0 → 1 → 6 → 7 → 8 → 7 → 5 → 3 → 5 → 9 → 4 → 2 → NULL
Figure it out!
We have a game for you to play. Rearrange the logical building blocks to develop a clearer understanding of how to solve this problem.
Try it yourself
Implement your solution in the following coding playground.
// Definition for a Linked List nod// class ListNode {// int val;// ListNode next;// // Constructor// public ListNode(int val) {// this.val = val;// this.next = null;// }// }import java.util.*;import ds_v1.LinkedList.ListNode;public class Solution{public static ListNode reverseKGroups(ListNode head, int k) {// Replace this placeholder return statement with your codereturn head;}}